(1)/(4))^(-3x+4)=8^(x-1)

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Solution for (1)/(4))^(-3x+4)=8^(x-1) equation: 



(1)/(4))^(-3x+4)=8^(x-1)

We move all terms to the left:

(1)/(4))^(-3x+4)-(8^(x-1))=0

We multiply all the terms by the denominator


-3x*4)^(+4)-(8^(x-1))+1=0

We add all the numbers together, and all the variables

-3x*4)^4-(8^(x-1))+1=0

Wy multiply elements

-12x^2=0

a = -12; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·(-12)·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{-24}=0$

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